Question

PLZ HELP ASAP. VERY MUCH NEEDED...

Answer 1

`\large \boxed{\text{1.23 g/L}}`

Step-by-step explanation:

We can use the Ideal Gas Law to calculate the density of the gas.

pV = nRT

n = m/M Substitute for n

pV = (m/M)RT Multiply both sides by M

pVM = mRT Divide both sides by V

pM = (m/V) RT

ρ = m/V Substitute for m/V

pM = ρRT Divide each side by RT

`\rho = (pM )/(RT)`

Data:

The gas is N₂ at STP (0 °C and 1 bar)

p = 1 bar

M = 28.01 g/mol

R = 0.083 14 bar·L·K⁻¹mol⁻¹

T = 0 °C = 273.15 K

ρ = (1 × 28.01)/(0.083 14 × 273.15) = 1.23 g/L

`\text{The density of the gas is $\large \boxed{\textbf{1.23 g/L}}$}`

It appears that you are using the old definition of STP. Standard pressure has been defined as 1 bar since 1982.