Question

A ball is thrown straight up with an initial speed of 36 m/s . Part A How much time does it take for the ball to reach the top of its trajectory?

Answer 1

Answer:3.67 s

Step-by-step explanation:

Given

Ball is thrown with an initial velocity of
`u=36\ m/s`

As the ball moves upward it experience a declaration due to gravity which will slow down the ball

using

`v=u+at`

where v=final velocity

u=initial velocity

a=acceleration

t=time

Here
`v=0`

`0=36-9.8* t`

`t=(36)/(9.8)`

`t=3.67\ s`