Question

A strong man is compressing a lightweight spring between two weights. One weight has a mass of 2.3 kgkg , the other a mass of 5.3 kgkg . He is holding the weights stationary, but then he loses his grip and the weights fly off in opposite directions. The lighter of the two is shot out at a speed of 6.0 m/sm/s .

Answer 1

Incomplete question.The complete question is here

A strong man is compressing a lightweight spring between two weights. One weight has a mass of 2.3 kgkg , the other a mass of 5.3 kgkg . He is holding the weights stationary, but then he loses his grip and the weights fly off in opposite directions. The lighter of the two is shot out at a speed of 6.0 m/sm/s .What is the speed of the heavier weight?

Answer:

`v_(2f)=2.60m/s`

Step-by-step explanation:

Given data

First weight mass m₁=2.3 kg

Second weight mass m₂=5.3 kg

Lighter weight speed v₁i= -6.0 m/s

To find

Heavier weight velocity v₂f

Solution

From law of conservation of momentum

`p_(f)=p_(i)\\ m_(1)v_(1f)+m_(2)v_(2f)=m_(1)v_(1i)+m_(2)v_(2i)\\as\\v_(1i)=v_(2i)=0\\So\\ m_(1)v_(1f)+m_(2)v_(2f)=0\\ m_(1)v_(1f)=-m_(2)v_(2f)\\v_(2f)=(( m_(1)v_(1f))/(-m_(2)) )\\v_(2f)=(( 2.3kg*(-6.0m/s))/(-(5.3kg)) )\\v_(2f)=(-13.8/-5.3)\\v_(2f)=2.60m/s`