Question

A boat crosses a river of width 244 m in which the current has a uniform speed of 1.99 m/s. The pilot maintains a bearing (i.e., the direction in which the boat points) perpendicular to the river and a throttle setting to give a constant speed of 1.68 m/s relative to the water. How far downstream from the initial position is the boat when it reaches the opposite shore

Answer 1

Answer:289.02\ m

Step-by-step explanation:

Given

width of river
`d=244\ m`

velocity of current
`v_1=1.99\ m/s`

Velocity of boat w.r.t to current
`v_(21)=1.68\ m/s` perpendicular to current

therefore Perpendicular component of velocity will help boat to cover the width of river in
`t_1` time which is given by

`t_1=(244)/(v_(21))`

`t_1=(244)/(1.68)=145.23\ s`

In this time current will drift the boat a distance of

`x=v_1* t_1`

`x=1.99* 145.23`

`x=289.02\ m`