Answer:
The gate will open if the height of water is equal to or more than 0.337m.
Step-by-step explanation:
From the diagram attached, (as seen from the reference question found on google)
The forces are given as
Force on OA
![F_1=P A_1\\F_1=\rho g \bar{h} A_(OA)](https://img.qammunity.org/2021/formulas/physics/college/6bg9ddglx872mg94m1mvwssspdzyggnclm.png)
Here
- ρ is the density of water.
- g is the gravitational acceleration constant
is the equivalent height given as
![\bar{h}=h+(0.6)/(2)\\\bar{h}=h+0.3](https://img.qammunity.org/2021/formulas/physics/college/aaobukxo0aeqw1j8i24q9g0egma1cwjmq3.png)
is the area of the OA part of the door which is calculated as follows:
The Force is given as
![F_1=0.6\rho g[h+0.3]](https://img.qammunity.org/2021/formulas/physics/college/oxe0242dken4w9ak32n52ulpfkt5q8m8jc.png)
Force on OB
![F_2=P A_2\\F_2=\rho g \bar{h} A_(OB)](https://img.qammunity.org/2021/formulas/physics/college/kvk98ny2p8nohuyxxgxjokm8c5o5f8xy63.png)
Here
- ρ is the density of water.
- g is the gravitational acceleration constant
is the equivalent height given as
![\bar{h}=h+0.6+(0.4)/(2)\\\bar{h}=h+0.8](https://img.qammunity.org/2021/formulas/physics/college/5vfi0unkolgaxptla7jk8usf990uzwxwa8.png)
is the area of the OB part of the door which is calculated as follows:
![A_(OB)=L* W\\A_(OB)=1* 0.4\\A_(OB)=0.4 m^2](https://img.qammunity.org/2021/formulas/physics/college/isefn4hzua1e1w75kohro5ne6rmqbo5tsy.png)
The Force is given as
![F_2=0.4\rho g[h+0.8]](https://img.qammunity.org/2021/formulas/physics/college/tsya5dh5pd9rzxkao6rq77tbpacfux32xb.png)
Now the moment arms are given as
![\bar{y}_a=\bar{h}+\frac{I}{A\bar{h}}\\\bar{y}_a=h+0.3+((1)/(12)* 0.6^3 * 1)/(0.6 *[h+0.3])\\\bar{y}_a=h+0.3+(0.03)/(h+0.3)](https://img.qammunity.org/2021/formulas/physics/college/s58ukml7yf9bmgwgrkcr3vv8g6z96wgvn2.png)
![\bar{y}_b=\bar{h}+\frac{I}{A\bar{h}}\\\bar{y}_b=h+0.8+((1)/(12)* 0.4^3 * 1)/(0.4 *[h+0.8])\\\bar{y}_b=h+0.8+(0.0133)/(h+0.8)](https://img.qammunity.org/2021/formulas/physics/college/kc1igmsv9dpzsxafotuvli1wadruhlps2u.png)
Taking moment about the point O as zero
![F_1(h+0.6-\bar{y}_a)=F_2(\bar{y}_b-h+0.6)\\F_1(h+0.6-h-0.3-(0.03)/(h+0.3))=F_2(h+0.8+(0.0133)/(h+0.8)-h-0.6)\\F_1(0.3-(0.03)/(h+0.3))=F_2(0.2+(0.0133)/(h+0.8))\\0.6\rho g[h+0.3](0.3-(0.03)/(h+0.3))=0.4\rho g[h+0.8](0.2+(0.0133)/(h+0.8))\\0.6[h+0.3](0.3-(0.03)/(h+0.3))=0.4[h+0.8](0.2+(0.0133)/(h+0.8))\\0.18h -0.054-0.018=0.08h+0.064+0.00533\\h=0.337 m](https://img.qammunity.org/2021/formulas/physics/college/7eufjrosq9b6ler8fo23ng1lfqbyr8ggwv.png)
So the gate will open if the height of water is equal to or more than 0.337m.