Answer:
The plane should drop the package 632.8m away from the scientists
Step-by-step explanation:
Given data
Our origins is the plane in the moment it drops the package
The positive vertical direction is upward
The positive horizontal direction is to the right
![v_(ix)=140 m/s\\v_(iy)=0m/s\\y_(f)=-100m\\y_(i)=0m\\x_(i)=0m](https://img.qammunity.org/2021/formulas/physics/college/g1pfjhuoycf259obkxey1r2ep1y46sny0v.png)
From equation of simple motion we know
![y_(f)=y_(i)+v_(iy)t+(1/2)at^(2)\\ -100m=0+0+(0.5*-9.8m/s^(2)*t^(2) )\\t=√((100/4.9)) \\t=4.52s](https://img.qammunity.org/2021/formulas/physics/college/uv1rbs3rzn8w14rwlhegd4g59dxix2qk8k.png)
From horizontal velocity:
![v_(x)=(x_(f)-x_(i))/(t)\\140m/s=(x_(f)-0m)/(4.52s)\\ x_(f)=140*4.52\\x_(f)=632.8m](https://img.qammunity.org/2021/formulas/physics/college/wnsigugdyiy7ubc6e45oe2gs9t4w6ko9en.png)
The plane should drop the package 632.8m away from the scientists