A certain television is advertised as a 45-inch TV (the diagonal length). If the width of the TV is 36 inches, how many inches tall is the TV?

Question

asked Oct 11, 2021 86.6k views

2 Answers

Xyz Rety · Answer 1 · 2021-10-15T02:20:19+0000

For this case we have that by definition, the Pythagorean theorem states that:

c ^ 2 = a ^ 2 + b ^ 2

Where:

c: It is the hypotenuse of the right triangle

a, b: They are the legs of the triangle

According to the data of the statement we have:

$c = 45 \ in\\b = 36 \ in$

We have to:

$a ^ 2 = c ^ 2-b ^ 2\\a = \sqrt {c ^ 2-b ^ 2}\\a = \sqrt {45 ^ 2-36 ^ 2}\\a = \sqrt {2025-1296}\\a = \sqrt {729}\\a = 27 \ in$

So, the height of the TV is
$27 \ in$

Answer:

$27 \ in$