The given question is incomplete. The complete question is as follows.
A 56-kg hiker is climbing the 828-m-tall Burj Khalifa in Dubai. If the efficiency of converting the energy content of the bars into the work of climbing is 25%, the remaining 75% of the energy released through metabolism is heat released to her body. She eats two energy bars, one of which produces 1.10×103kJ of energy upon metabolizing. Assume that the heat capacity of her body is equal to that for water (75.3 Jmol−1⋅K−1). Calculate the increase in her temperature at the top of the structure.
Calculate the temperature at the top of the structure. Assume her intitial temperature to be
.
Step-by-step explanation:
Energy present in total of two bars is as follows.
![2 * 1.2 * 10^(3) kJ](https://img.qammunity.org/2021/formulas/chemistry/college/8kpzylert7ly2usubuqrb3atpwkb6stbzc.png)
kJ
(as 1 kJ = 1000 J)
As 75% of energy releases out. Let us assume that energy releases out of its body be E. Then, energy will be calculated as follows.
E =
![(75)/(100) * 2.4 * 10^(6) J](https://img.qammunity.org/2021/formulas/chemistry/college/w89u8vkxuzaqwu1z8ssefdh30vbasi02pl.png)
=
J
Given data is as follows.
mass (m) = 56 kg
= 56000 g (1 kg = 1000 g)
Specific heat = 4.18
![J/g ^(o)C](https://img.qammunity.org/2021/formulas/chemistry/college/44k130c043ij4amuo2lsgip2meoctvg7lz.png)
As heat is releasing which means that value of E will be negative.
-E =
![-(180 * 10^(4) = 56000 g * 4.18 * (T_(2) - 36.6)^(o)C](https://img.qammunity.org/2021/formulas/chemistry/college/f1k9oxpmwyj6uxvdlf9r6aco3d3pina5vd.png)
![T_(2) = 28.74^(o)C](https://img.qammunity.org/2021/formulas/chemistry/college/p61hpn2y2yp9hy66wbffrj3o8juizw3sv7.png)
Her temperature at the top of the structure is
.
Now, change in temperature is calculated as follows.
![\Delta T = (36.6 - 28.74)^(o)C](https://img.qammunity.org/2021/formulas/chemistry/college/8qxru3saa8tnvfx4lk6gg0lg8mafewqdki.png)
=
![7.86^(o)C](https://img.qammunity.org/2021/formulas/chemistry/college/2yldvxjwpxrob44r7h289cje9wusz1fmp3.png)
Thus, we can conclude that increase in her temperature at the top of the structure is
.