Question

10 mol/s of ethylbenzene is compressed isentropically in a steady-flow process from 1 bar and 200°C to 14 bar. Assuming an ideal gas at all times, find the final temperature. (An ideal gas at 14 bar?

Answer 1

Step-by-step explanation:

Given ;

• n = 10mols, P1 = 1 bar, P2 = 14 bar, T1 = 200degree Celsius = 473K

• for reversible adiabatic Q = 0

• W = γ/γ - 1 x P1V1 [ 1 - (P2/P1)^γ-1/γ]

• Heat capacity ratio of ethyl benzene = γ = 1.05332

• molar mass of ethyl benzene = 106g/mol

• plugging the values in the above equation, W = -110988.12WATT

From first law ; Q - W = MCp dT

• Cp = 1.55J/gk = heat capacity of ethyl benzene

• M = number of moles X molar mass

• = 10mol/s X 106g/mol = 1060gs

plugging the values in the new equation ;

• Q - W = nCp(T2 - T1)

• T2 = 540.5K = final temperature