Question

A square that has 28 cm long edges is centered on the x-axis in a region where there exists a uniform electric field given by = (1.2 kN/C). What is the electric flux of this electric field through the surface of a square if the normal to the surface is in the +x direction?

Answer 1

Explanation:

• From ΦE = ∫s E * dA

• Given E= 1.2 kN/C = 1200N/C

• L = 28cm = 0.28m

• A = Area = (0.28)^2 = 0.0784m^2

• electric flux = EA = 1200N/C x 0.0784m^2

= 94.08Nm2/C