Question

Given s (t )equals 3 t squared plus 6 ts(t)=3t2+6t​, where​ s(t) is in feet and t is in​ seconds, find each of the following. ​a)​ v(t) ​b)​ a(t) ​c) The velocity and acceleration when tequals=22 sec

Answer 1

The correct question is:

Given s(t) = 3t² + 6t​, where​ s(t) is in feet and t is in​ seconds, find each of the following. ​

a)​ v(t) ​

b)​ a(t) ​

c) The velocity and acceleration when t =22 sec

Solution:

Given s(t) = 3t² + 6t

(a) The velocity, v(t) is the derivative of s(t). That is v(t) = s'(t)

s'(t) = v(t) = 6t + 6

(b) The acceleration, a(t) is the derivative of v(t). That is a(t) = v'(t)

v'(t) = a(t) = 6

(c) When t = 22 sec,

v(t) = v(22) = 6(22) + 6 = 132 + 6

= 138

a(t) = a(22) = 6

At t = 22, the velocity is 138, and acceleration is 6.