Question

The waterfall viewed in flooding has a width of approximately 16 feet across. The channel depth during flooding is approximately 8 feet deep, and the velocity is approximately 15 ft/second. What is the approximate discharge of the water as it flows down the waterfall

Answer 1

The approximate discharge of the water as it flows down the waterfall is 1920
`(ft^(3) )/(second)`

Step-by-step explanation:

Calculate cross-sectional area:

Cross-sectional area = 16 ft x 8 ft = 128
`ft^(2)`

Velocity = 15
`(ft)/(second)`

Calculate discharge in feet per second:

Discharge = 128
`ft^(2)` x 15
`(ft)/(s)` = 1920
`(ft^(3) )/(s)`