Answer:
Explanation:
Alright, lets get started.
Suppose the first fraction is :
![(a)/(b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4csve9ghyam2nxyvna10u6d4e3rld2pfoh.png)
Suppose the second fraction is :
![(c)/(d)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dhplxus3jhsn4koj2rddptbfq3autuxk39.png)
The sum of both fraction is given as :
![(5)/(6)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vlc24zkrkzsawjdlnplhlwtdg6qr58ndbp.png)
.......................equation (1)
The difference of both fraction is given as :
![(1)/(2)](https://img.qammunity.org/2021/formulas/physics/middle-school/ukxexrkoplrwscaxd96qbbkphc5fo6w2ur.png)
.........................equation (2)
Adding equation (1) and equation (2)
![(c)/(d) \ will \ be \ cancelled](https://img.qammunity.org/2021/formulas/mathematics/high-school/zljnlqta9hw7akp3mq0y0groucnpy11x4y.png)
![(2a)/(b)=(5)/(6)+(1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yewr6rm9v6hrgy5t79yen2sqf4mvb2dh3k.png)
making common denominator
![(2a)/(b)=(5)/(6)+ (3)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/heecunhz0rct42tfjk4o7hr3dw1ns2sj5t.png)
![(2a)/(b)=(8)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/c5vxqcl4reywncnpova0uexy5iqclxvuv4.png)
Hence,
![(a)/(b)=(2)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/rqnkddxvotkzc95xe5zmrzgtbzen8w6bn3.png)
Plugging the value of
in equation (1)
![(2)/(3)+(c)/(d)=(5)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/t9m3sxquz4wtidynllbff7v4s7it0ap5dt.png)
Subtracting
in both sides
![(c)/(d)=(5)/(6)-(2)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/1ftk21q1tlnomeul1aieq3ibbl1ovdv3my.png)
![(c)/(d)=(1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4iyij0xnp2sydulxqqikn5rhcho9co0plw.png)
Hence both fractions are
...................Answer
Hope it will help :)