Question

When using a one-tailed test and a sample size of 24, what is the probability of a value being to the left of a number that has a student-t statistic of –2.50?

Answer 1

P-value = 0.009997

Explanation:

We are given the following in the question:

Sample size, n = 24

Nature of test: One-tailed test(Left tailed test)

`t_{\text{statistic}} = -2.50`

We have to calculate the p-value.

Degree of freedom = n - 1 = 23

We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.

P-value = 0.009997

0.009997 is the probability of a value being to the left of a number that has a student-t statistic of –2.50.