Question

Assume that in squashes the difference in fruit weight between a 3-lb type and a 6-lb type results from three independently segregating allele pairs, A/a, B/b, and C/c. Each capital-letter allele contributes a half-pound to the weight of the squash. From a cross of a 3-lb plant (aa bb cc) with a 6-lb plant (AA BB CC), what will be the phenotypes (weights) of the F1 AND F2? What will be their distribution?

Answer 1

F1: Aa Bb Cc: 4.5 lbs

F2: Too many to list: Between 3 lbs and 6 lbs

Step-by-step explanation:

F1: Aa Bb Cc, will be the genotypes and will weigh 4.5 lbs, the reason for that is because each capital letter allele adds half a pound to the base weight of 3 lbs.

F2: There are many different genotypes that can be present in the second generation, for example (AA BB CC, AA BB Cc, AA BB cc, etc.) each of which will allow the plant to grow to a certain height. The majority of phenotypes will be 4.5 lbs. There will be one who is AA BB CC, and another one person who has the code, aa bb cc.