Question

You hang a heavy ball with a mass of 94 kg from a platinum rod 3.2 m long by 2.2 mm by 3.1 mm. You measure the stretch of the rod, and find that the rod stretched 0.002588 m. Part 1 (a) Using these experimental data, what value of Young's modulus do you get? Y= N/m2 the tolerance is +/-2% By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor.

Answer 1

`1.67* 10^(11) N/m^2`

Step-by-step explanation:

Mass of the ball,
`m=94 kg`

Force = weight of the ball

`F=mg = 94kg* 9.81 m/s^2=922.14N`

For Young's modulus, substitute the values in the formula which is as follows:

`(F)/(A)=Y(\Delta L)/(L)\\\Rightarrow Y= (FL)/(A\Delta L)\\\Rightarrow Y =(922.14 * 3.2)/(2.2* 10^(-3)* 3.1* 10^(-3) * 0.002588)=1.67* 10^(11) N/m^2`