Question

A solid sphere of radius 37 cm has a to- tal positive charge of 14.6 μC uniformly dis- tributed throughout its volume. Calculate the magnitude of the electric field at the center of the sphere.

Answer 1

Electric field at the center will be zero

Step-by-step explanation:

Data provided in the question:

Radius of the solid sphere, R = 37 cm

Total positive charge, q = 14.6 μC

Now,

By Gauss law , we know that

E(4πr²) = Qε₀

E is the electric field

Q =
`\rho ((4)/(3)\pi r^3)`

Thus,

E(4πr²) =
`(\rho ((4)/(3)\pi r^3))/(\epsilon_0)`

or

E =
`(\rho r)/(3\epsilon_0)`

here,

r is the distance of the point of observation from the center of the sphere,

at the center r = 0

Hence,

Electric field at the center will be zero