Answer:
14.14
![m^(3)](https://img.qammunity.org/2021/formulas/physics/middle-school/a5vkxzl4vrsq35w1l5kk5h760ybrqtuw2p.png)
Explanation:
volume of a sphere (ball) =
![(4)/(3) \pi r^(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/afq76xohgkhh3p481plkg3y2sa32u7t1dx.png)
volume of inner ball =
= 4.2
![m^(3)](https://img.qammunity.org/2021/formulas/physics/middle-school/a5vkxzl4vrsq35w1l5kk5h760ybrqtuw2p.png)
⇒
=
![(4.2 X 3)/(4\pi )](https://img.qammunity.org/2021/formulas/mathematics/high-school/5nrnqmr7qrk8gg1c7qi114pw0uj9mln5jq.png)
⇒
= ∛ 1.00268
⇒
= 1
![m^(3)](https://img.qammunity.org/2021/formulas/physics/middle-school/a5vkxzl4vrsq35w1l5kk5h760ybrqtuw2p.png)
radius of outer ball is 1.5 times larger than radius of inner ball, therefore;
⇒ R = 1.5 r
⇒ R = 1.5 x 1 = 1.5
![m^(3)](https://img.qammunity.org/2021/formulas/physics/middle-school/a5vkxzl4vrsq35w1l5kk5h760ybrqtuw2p.png)
Volume of outer ball = (4/3)
x
= 14.14
![m^(3)](https://img.qammunity.org/2021/formulas/physics/middle-school/a5vkxzl4vrsq35w1l5kk5h760ybrqtuw2p.png)