Answer:
a) Age of the three microbacteria J=0.00099 days
b) Age of the microbacteria M=0.00011 days
Explanation:
a)We first calculate the age of a single microbacterium J, as follows:
Age of microbacteria J=(1/3)^-3=0.00033 days
The total age of the three microbacteria J is equal to:
Age of the three microbacteria J=3x0.00033=0.00099 days
b) If a microbacteria M lives the third part of what the microbacterium J lives, only the age of the microbacteria J must be divided by three, thus:
Age of microbacteria M=0.00033/3=0.00011 days