Answer:
The coefficient of restitution is greater in a head-on collision
Step-by-step explanation:
Let m be the masses of the electric vehicles and v be their initial speeds. Since they are moving in opposite directions, the momentum, p₁ of the first electric vehicle = mv and that of the second vehicle is p₂ = -mv. Let p₃ and p₄ be their final momenta. From the law of conservation of momentum, momentum before impact = momentum after impact.
So, p₁ + p₂ = p₃ + p₄
mv + (-mv) = p₃ + p₄
mv - mv = p₃ + p₄
0 = p₃ + p₄
p₃ = -p₄
mv₃ = -mv₄
v₃ = -v₄. where v₃ and v₄ are their final velocities. This shows that their final velocities are not zero. So they do not come to a stop.
Now, we calculate the coefficient of restitution, e = -(v₄ - v₃)/(v₂ - v₁) = -(v₄ -
(-v₄))/(-v - (v))= - (v₄+ v₄)/-(v + v) = 2v₄/2v = v₄/v. Since e ≠ 0, the vehicles do not come to a stop
Head-on collisions are more jarring because, the coefficient of restitution is greater in an head-on collision because, the maximum value of the velocity is used by the electric vehicles. They only have velocity components in one direction, thereby, having a maximum value for the coefficient of restitution.