Question

Find the vertex of the function given below.
у = 2х^2 + 8х + 1​

Answer 1

Explanation:

hello :

у = 2х² + 8х + 1​

y= 2(x²+4x+4-4)+1

y = 2(x+2)²-8+1

y= 2(x+2)²-7....vertex form

the vertex is : (-2 ; -7)

Answer 2

the answer is (-2,-7)