Question

What is the number of millimoles of H+ in 1.653 mmol of oxalic acid dehydrate?Remember that oxalic acid is diprotic.

Answer 1

Answer: 3.306 mmol

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

Molarity

n= moles of solute

`V_s` = volume of solution in ml

`C_2O_4H_2.2H_2O\rightarrow C_2O_4^(2-)+2H^++2H_2O`

According to stoichiometry:

1 mole of
`C_2O_4H_2` gives 2 moles of
`H^+`

1.653 mmol of
`C_2O_4H_2` gives =
`(2)/(1)* 1.653=3.306mmo` of
`H^+`

Thus number of millimoles of
`H^+` are 3.306