Question

5.

A stone is held at a height h above the ground. A second stone with four times the mass of the first
one is held at the same height. The gravitational potential energy of the second stone compared to that
of the first stone is -

Answer 1

`U_(2)=4U_(1)`

Step-by-step explanation:

Let U1 and U2 be the gravitational potential energy of the first and second stone respectively.

U1 is given by:

`U_1 = (m)gh\\`

and U2 is given by:

`U_2 = (4m)gh`

therefore, comparing the energies we have:

`(U_2)/(U_1) = ((4m)gh)/((m)gh)= 4`

therefore:

`U_2=4U_1`