Question

The charges are in a uniform electric field whose direction makes an angle of 36.3 ∘∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.60×10−9 N⋅mN⋅m ?

Answer 1

E=828N/C

Step-by-step explanation:

Suppose the point charges are q1=-500nC

q2=+500nC

Distance(l)=3.10mm

Now to calculate dipole moment:

Dipole moment (p)=q*l

=(5.0*10'-9C)(3.10*10'-3m)

p=15.50*10'-12C.m

Now to calculate magnitude:

E=torque(£)/psin@=7.6*10'-9/(15.50*10'-12C.m)(sin36.3)

E=7.6*10'-9/9.17*10'-12

E=828N/C

Or

E=8.28*10'2N/C