Answer:
Kinetic Enerrgy = 12744000 J or 12.744 MJ
Step-by-step explanation:
Given Data:
Mass of fragment = m =1770 kg ;
Estimated speed = v = 120 m/sec ;
Solution:
As we know that
Kinetic energy = K.E = (1/2)mv²
By putting the values, we get
K.E = 0.5*1770*120²
K.E = 12744000 J
or
K.E = 12.744 MJ
So, the kinetic energy of lead-lined vault when it landed was 12.744MJ approximately.