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A house is maintained at 1 atm and 24 oC, and warm air inside a house is forced to leave the house at a rate of 150 m3 /h as a result of outdoor air at 5 oC infiltrating into the house through the cracks. Determine the rate of net energy loss of the house due to mass transfer.

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Answer:

1.045 KW

Step-by-step explanation:

Rate of heat transfer is determined with the rate of change of specific enthalpy of the air.

Using relation

Q= mCpΔT

=рVCpΔT


=\frac{P}{RTin_{} } VCp (
(Tin_{} -Tout_{} )

=(101.35/0.287×297)×150×1.005(24-5)/1×60×6=1.045 KW

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