Question

Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K .

Answer 1

`4.0932672025* 10^(-17)`

Step-by-step explanation:

`E_a` = Activation energy = 160 kJ

T = Temperature = 510 K

R = Universal gas constant = 8.314 J/mol K

The fraction of energy is given by

`f=e^{-(E_a)/(RT)}\\\Rightarrow f=e^{-(160000)/(8.314* 510)}\\\Rightarrow f=4.0932672025* 10^(-17)`

The fraction of energy is
`4.0932672025* 10^(-17)`