163k views
0 votes
The height in feet of an arrow t seconds after it was shot into the air is given by the function: h(t)= -16t^2+288t+6

The arrow will hit the ground after _____ seconds. (Round to the nearest second)

(Please explain!)

User Mitsu
by
8.0k points

1 Answer

2 votes

-16t²+288t+6

use t=-b+/-√b²-4ac÷2a

t= -288+/-√288²-4(-16)(6)÷2a

2+/-√2580=0

2+√2580= 53 seconds 2-√2580= 49 seconds

the arrow will hit the ground after 53 seconds or 49 seconds

User Steven Smethurst
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories