Question

alpha decay is a nuclear decay in which a helium nucleus is emitted. If the helium nucleus has a mass of 6.8*10^-27 kg and is given 5.8 MeV of kinetic energy what is its velocity

Answer 1

16520931.465 m/s

Step-by-step explanation:

K = Kinetic energy = 5.8 MeV

m = Mass of nucleus =
`6.8* 10^(-27)\ kg`

Speed of a particle is given by

`v=\sqrt{(2K)/(m)}\\\Rightarrow v=\sqrt{(2* 5.8* 10^6* 1.6* 10^(-19))/(6.8* 10^(-27))}\\\Rightarrow v=16520931.465\ m/s`

The velocity is 16520931.465 m/s