Answer:
The vectors are linearly independent
Explanation:
These vectors can be written in a matrix form as:
![\left[\begin{array}{ccc}5&-2&4\\2&-3&5\\4&5&-7\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/46smo4kg8insg6s7smlee4j8frzefpmnhl.png)
and if the matrix is invertible, the system has a unique solution, and hence, the vectors that form the matrix are linearly independent.
A matrix is invertible if it's determinant is different from zero.
Suppose A is a matrix, A is invertible if |A| ≠ 0

=

=
![= 5[-7(-3) - 5(5)] + 2[2(-7) - 4(5)] + 4[5(2) - 4(-3)]\\= 5(21 - 25) + 2( -14 -20) + 4(10 + 12)\\= 5(-4) + 2(-34) + 4(21)\\= -20 - 68 + 84\\= -4\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/gw4gwh7gtz82ijkjmhfcyukz20bxpa0bge.png)
Since this is not zero, we conclude that the vectors are linearly independent.