Answer:
26.6 s.
Step-by-step explanation:
For a zero order kinetics, the formula is:
[A] = [A₀] - kt
where,
[A] = amount pr concentration left
[A₀] = initial concentration or amount
k = rate constant
t = time
concentration = mole/volume
[A₀] = 0.5/2.0
= 0.25 M
[A] = 0.25/2.0
= 0.125 M
k = 0.0047 Ms⁻¹
t = ([A] - [A₀]/-k
= (0.125 - 0.25)/(-0.0047)
= 26.60 s.
the amount is reduced by half after 26.6 seconds