Question

A steel cable has a cross-sectional area 2.54 10-3 m2 and is kept under a tension of 1.01 104 N. The density of steel is 7860 kg/m3. Note that this value is not the linear density of the cable. At what speed does a transverse wave move along the cable.

Answer 1

The speed is equals to 22.49 m/s

Step-by-step explanation:

Given Data:

`Area = A=2.54*10^-^3m^2\\Force = F = 1.01*10^4N\\density = p = 7860 kg/m^3`

Required:

Speed of Traverse wave = c =?

Solution:

As we know that

`p=m/V\\\\ p=m/(L*A)\\p*A=m/L`

Now the equation for speed of traverse wave is calculated through:

`\sqrt (F*L)/(m)\\`

=
`\sqrt(F)/(m/L) \\\sqrt{} (F)/(p*A)`

Substituting the values

`\sqrt(1.01*10^4)/(7860*2.54*10^-^3) \\`

=22.49 m/s