Answer:
- 32,283 years old
- 31,718 years old
Explanation:
If h is the half-life of the radioactive substance, then the proportion remaining after t years is ...
k = (1/2)^(t/h)
We can find the value of t using logarithms:
log(k) = (t/h)·log(1/2)
t = h·log(k)/log(1/2)
__
a) For k = 2% and h = 5720 years, we have ...
t = 5720·log(.02)/log(.5) ≈ 5720·5.64386
t ≈ 32,283 . . . . years old
__
b) For k = 2% and h = 5620 years, we have ...
t ≈ 5620·5.64386 ≈ 31,718 . . . . years old
_____
Note the proportionality of age to half-life. Once we found the multiplier corresponding to 2% remaining, we can use that for any estimate of the half-life.