154k views
5 votes
Find the arc length of the curve below on the given interval. y equals 2 x Superscript 3 divided by 2 on [0 comma 9 ]

1 Answer

2 votes

Answer:

d=54.93

Explanation:

From exercise we have y=2x^{3/2} on interval [0,9]

We calculate the arc length of the curve on the given interval.

We have the formula:

d=\int\limits^a_b {\sqrt{1+f'(x)^2}} \, dx

we get

f(x)=y=2x^{3/2}

f'(x)=y'=3x^{1/2}

d=\int\limits^9_0 {\sqrt{1+(3x^{1/2})²}\, dx

d=\int\limits^9_0 {\sqrt{1+9x}}\, dx

d=[\frac{2·(9x+1)^{3/2}}{27}]_0^9

d=\frac{2·(82^{3/2}-2)}{27}

d=54.93

We use the site geogebra.org to drawn a graph.

Find the arc length of the curve below on the given interval. y equals 2 x Superscript-example-1
User Jenny Blunt
by
6.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.