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A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 18 went to right center field, 12 went to center field, 10 went to left center field, and 1 went left field.

(a) What is the probability that a randomly selected home run was hit to leftleft ​field?
(b) Was it unusual for this player to hit a home run to leftleft ​field?

User Jitender
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1 Answer

3 votes

Answer:

(a) 1/60

(b) Yes, it was unusual.

Step-by-step explanation:

Number that went to the right field = 19

Number that went to the right center field = 18

Number that went to the center field = 12

Number that went to the left center field = 10

Number that went to the left field = 1

Total number of home runs = 60

(a) The probability that a randomly selected home run was hit to left ​field is

P(left field) = 1/60

(b) It was unusual because whenever a player hit a home run, it most times went to the right field,which is why the right field had the highest probability, 19/60.

On the other hand, it went to the left field the least number of times, which is why the left field had the least probability, 1/60.

So, it was unusual.

User David Morabito
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