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A bee with velocity vector r ′ ( t ) starts out at the origin at t = 0 and flies around for T seconds. Where is the bee located at time T if ∫ T 0 r ′ ( u ) d u = 0 ? What does the quantity ∫ T 0 ∥ r ′ ( u ) ∥ d u represent?

User Molleman
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1 Answer

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Answer:

At time T the bee will be at (0,0).

The quantity represents the integral of function
[r^(')(u)] with the time interval of (0,T).

Explanation:

Given :


\int\limits^T_0 {r^(')(u) } \, du=0

As we already know that


(dr(t))/(dt)=r^(')(t)

Thus we can say that


(dr(u))/(du)=r^(')(u)


dr(u)=r^(')(u)du

Now,
\int\limits^0_T {r^(')(u) } \, du =[r(u)]_(0)^T=r(t)-r(0)


r(t)-r(0)=0\\


r(t)=r(0)=(0,0)

So at time T the bee will be at (0,0).

User Franz Ebner
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