Question

Complex numbers are used in electronics to describe the current in an electric circuit. Ohm's law relates the current in a circuit, I, in amperes, the voltage of the circuit, E, in volts, and the resistance of the circuit, R, in ohms, by the formula E- IR. Solve the problem using this formula. Find E, the voltage of a circuit, if I (16 +) amperes and R=2+4) ohms (32 +66i volte.

Answer 1

E = 3072i - 5904ohms

Explanation:

From ohms law recalled that E = IR given already

E = voltage (volts)

I = Current (amps)

R = resistance (ohms)

Therefore, by substitution

I = 16i and R = (2+4)ohms(32+66i)

= 6(32+66i) ohms

= (192+396i)ohms

E = (16i)×(192+396i)

E = 3072i + 5904i²

Recall that i² = -1 from complex number

E = 3072i +5904(-1)

E = 3072i - 5904ohms