Question

Consider a 0.15-mm-diameter air bubble in a liquid. Determine the pressure difference between the inside and outside of the air bubble if the surface tension at the air-liquid interface is a. 0.1 N/m. b. 0.12 N/m.

Answer 1

a)
`\Delta P= 2666.66 Pa`

b)
`\Delta P= 3200 Pa`

Step-by-step explanation:

Given that

Diameter ,d= 0.15 mm

We know that pressure difference is given as

`\Delta P=(4\sigma )/(d)`

Now by putting the values

When surface tension 0.1 N/m :

The surface tension ,
`\sigma=0.1\ N/m`

`\Delta P=(4* 0.1 )/(0.15)* 10^3\ Pa`

`\Delta P= 2666.66 Pa`

When surface tension 0.12 N/m :

The surface tension ,
`\sigma=0.12\ N/m`

`\Delta P=(4* 0.12 )/(0.15)* 10^3\ Pa`

`\Delta P= 3200 Pa`

a)
`\Delta P= 2666.66 Pa`

b)
`\Delta P= 3200 Pa`