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The masses of blocks A and B are 20kg and 10kg, respectively. The blocks are initially at rest on the floor and are connected by a massless string passing over a massless and frictionless pulley. An upward force is applied to the pulley. Find the acceleration of block A and of block B if the magnitude of the force is

1 Answer

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Answer:

If the magnitude of the force is 124

Step-by-step explanation:

F= 124

T= 62N

Mg a= 200 N Mg b= 100N


a_(1)= 0
a_(2)=0


/a_(sys)/=
(EF)/(Mtot)

=
(+(20kg) (9.8M/s^(2) )- (10Kg)(9.8M/s^(2) ))/(30kg)

= 3.2
M/s^(2)

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