Answer:
Step-by-step explanation:
- Given Mass of 4mL of bleach solution = 4mL x 1.11 g/mL = 4.44g
- Mass of NaClO in 4.44g beach solution = 0.05 x 100 / 4.44g =1.126g
- Moles of NaClO = mass /molar mass
- molar mass of NaClO = 74.44g/mol
- moles = 1.126g/74.44g/mol = 0.0151moles
Now when 6mL of this solution is taken, moles of NaClO in this 6mL;
= 6mL x 0.0151moles /100mL = 0.000906moles
- This is added to 6mL dye. Therefore, total volume of solution = 12mL total volume = 0.012L
- hence, concentration of bleach (in M) in the reaction vessel ; number of moles/volume