Please hurry. Solve the equation

Question

asked Jan 14, 2021 207k views

1 Answer

Bandrami · Answer 1 · 2021-01-19T05:09:47+0000

The value of x is
$5\sqrt[3]{25}$ .

Solution:

Given expression is
$-7=8-3 \sqrt[5]{x^(3)}$ .

Switch both sides.

$8-3 \sqrt[5]{x^(3)}=-7$

Subtract 8 from both side of the equation.

$8-3 \sqrt[5]{x^(3)}-8=-7-8$

$-3 \sqrt[5]{x^(3)}=-15$

Divide by –3 on both side of the equation.

$$\frac{-3 \sqrt[5]{x^(3)}}{-3} =(-15)/(-3)$

$\sqrt[5]{x^(3)}=-5$

To cancel the cube root, raise the power 5 on both sides.

$(\sqrt[5]{x^(3)})^5=(-5)^5$

x^3=3125

To find the value of x, take square root on both sides.

$\sqrt[3]{x^3}=\sqrt[3]{25}$

$x=5\sqrt[3]{25}$

Hence the value of x is
$5\sqrt[3]{25}$ .