Answer:

So then the best answer for this case would be:
a. 13.6 minutes
Step-by-step explanation:
For this case we have the following data for the response rates:
17,12,9,16,14
And we want to calculate the mean response time for 911 calls in this village.
And for this case we use we can use the definition of sample mean given by:

Where n = 5 represent the sample size for this case. If we replace we got:

So then the best answer for this case would be:
a. 13.6 minutes
The sample mean is an estimator unbiased of the population mean because:

For this reason is a good statistic if we want to see central tendency in a group of values.