Question

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 4 kg, the acceleration of the object is 5 /ms2. If the same force acts upon another object whose mass is 10 kg, what is this object's acceleration?

Answer 1

`a = 2 (m)/(s^2)`

Explanation:

Knowing that
`F = ma` being
`m` the mass and
`a` the acceleration we have:

"When a certain constant force acts upon an object with mass 4kg the acceleration of the object is
`5 (m)/(s^2)`"

We can calculate that force as:
`F = ma = (4Kg) (5(m)/(s^2)) = 20 Kg(m)/(s^2) = 20 N`

Now, that force is being aplied to another objet whose mass is 10 Kg and we want to know its acceleration.

Clearing
`a` from the force equation we have:

`a = (F)/(m)` ("The acceleration of the object varies inversely with its mass")

Then,

`a = (F)/(m) = (20N)/(10Kg) =2 (m)/(s^2)`