Question

A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius?

Showing work is appreciated but not neccessary

Answer 1

V2 = 370.22 mL

Step-by-step explanation:

assuming ideal gas:

V1 = 490.0 mL = 0.490 L

T1 = - 35.0 °C ≅ 238 K

T2 = 42.0°C ≅ 315 K

⇒ V2 = ?

∴ assuming constant pressure, we can apply the Charles's law:

⇒ V1/T1 = V2/T2

⇒ V2 = V1T1/T2

⇒ V2 = ((0.490 L)(238 K))/(315 K)

⇒ V2 = 0.3702 L = 370.22 mL