Question

identical springs are placed side-by-side (in parallel), and connected to a large massive block. The stiffness of the 43-spring combination is 16770 N/m. What is the stiffness of one of the individual springs? ks= N/m

Answer 1

The stiffness of one of the individual spring is 390 N/m.

Step-by-step explanation:

It is given that 43 identical springs are placed side-by-side and connected to a large massive block.

The stiffness of the 43 spring combination is 16770 N/m

We need to find the stiffness of one of the individual springs. Let k is the stiffness of one spring. The effective spring stiffness of this width spring is given by :

`K=N* k`

`k=(K)/(N)`

`k=(16770\ N/m)/(43)`

k = 390 N/m

So, the stiffness of one of the individual spring is 390 N/m. Hence, this is the required solution.