Answer:
3.08 × 10⁻³ M
Step-by-step explanation:
A chemist prepares a solution by adding 422 mg (0.422 g) of Co(NO₃)₂. The moles of solute associated with this mass, considering that the molar mass is 182.94 g/mol, are:
0.422 g × (1 mol/182.94 g) = 2.31 × 10⁻³ mol
The volume of the solution is 750 mL = 0.750 L.
The molarity of Co(NO₃)₂ is:
M = moles of solute / liters of solution
M = 2.31 × 10⁻³ mol / 0.750 L
M = 3.08 × 10⁻³ M