Question

Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is −70.0 mV, and the potential outside is zero. What is the change in the electrical potential energy ΔU electric of the potassium ions as they move across the membrane?

Answer 1

Step-by-step explanation:

Relation between potential energy and charge is as follows.

U = qV

or,
`\Delta U = q * \Delta V`

=
`1.6 * 10^(-19) * 70 * 10^(-3)`

=
`112 * 10^(-22)` J

or, =
`1.12 * 10^(20) J`

Therefore, we can conclude that change in the electrical potential energy
`\Delta U` is
`1.12 * 10^(20) J`.