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A random sample has been selected from a population. The point estimate = 78.65 and margin of error E = 8.24 for a 90% confidence level have been calculated for you. Construct the confidence interval that corresponds to this information.

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Answer:

90% confidence interval: (70.41,86.89)

Explanation:

We are given the following in the question:

Point estimate = 78.65

Margin of error, E = 8.24

Confidence level = 90%

Significance level = 10%

Formula:


\text{Point estimate} \pm \text{Margin of error}

Putting the values, we get,


z_(critical)\text{ at}~\alpha_(0.10) = \pm 1.64


78.65 \pm 8.24 = (70.41,86.89)

(70.41,86.89) is the required 90% confidence interval.

User Neelabh Pant
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