Question

Suppose a monatomic ideal gas is contained within a vertical cylinder that is fitted with a movable piston. The piston is frictionless and has a negligible mass. The area of the piston is 3.02 10-2 m2, and the pressure outside the cylinder is 1.01 105 Pa. Heat (2105 J) is removed from the gas. Through what distance does the piston drop?

Answer 1

through a distance of 69cm

Step-by-step explanation:

heat energy = 2105 J

P = 1.01 × 10^5 Pa

A = 3.02 × 10^-2

P = F/A

and also W = PV

V = W/P = 2105/ 1.01 × 10^5

V = 0.0208 m³

V = Ah

h = V/A

h = 0.0208/3.02 × 10^-2

h = 0.69 m

h = 69cm