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Two identical metal spheres A and B are connected by a metal rod. Both are initially neutral. 1.0x10^12 electrons are added tothe sphere A, then the connecting rod is removed.

Afterwards what is the charge of A and the charge ofB?

Answer 1

Charge on each metal sphere will be
`8* 10^(8)C`

Step-by-step explanation:

We have given number of electron added to metal sphere A
`n=10^(12)electron`

As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.

So electron on both the spheres
`=(10^(12))/(2)=5* 10^(11)electron`

We know that charge on each electron
`e=1.6* 10^(-19)C`

So charge on both the spheres will be equal to
`q=1.6* 10^(-19)* 5* 10^(11)=8* 10^(8)C`

So charge on each metal sphere will be equal to
`8* 10^(8)C`